Optimal. Leaf size=229 \[ \frac{10 b d^2 n \text{PolyLog}\left (2,-\frac{e x}{d}\right )}{e^6}+\frac{d^2 \log \left (\frac{e x}{d}+1\right ) \left (60 a+60 b \log \left (c x^n\right )+47 b n\right )}{6 e^6}-\frac{x^4 \left (5 a+5 b \log \left (c x^n\right )+b n\right )}{6 e^2 (d+e x)^2}-\frac{x^3 \left (20 a+20 b \log \left (c x^n\right )+9 b n\right )}{6 e^3 (d+e x)}-\frac{x^5 \left (a+b \log \left (c x^n\right )\right )}{3 e (d+e x)^3}+\frac{x^2 \left (60 a+60 b \log \left (c x^n\right )+47 b n\right )}{12 e^4}-\frac{d x (60 a+47 b n)}{6 e^5}-\frac{10 b d x \log \left (c x^n\right )}{e^5}+\frac{10 b d n x}{e^5}-\frac{5 b n x^2}{2 e^4} \]
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Rubi [A] time = 0.319522, antiderivative size = 260, normalized size of antiderivative = 1.14, number of steps used = 15, number of rules used = 10, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.476, Rules used = {43, 2351, 2295, 2304, 2319, 44, 2314, 31, 2317, 2391} \[ \frac{10 b d^2 n \text{PolyLog}\left (2,-\frac{e x}{d}\right )}{e^6}+\frac{d^5 \left (a+b \log \left (c x^n\right )\right )}{3 e^6 (d+e x)^3}-\frac{5 d^4 \left (a+b \log \left (c x^n\right )\right )}{2 e^6 (d+e x)^2}-\frac{10 d^2 x \left (a+b \log \left (c x^n\right )\right )}{e^5 (d+e x)}+\frac{10 d^2 \log \left (\frac{e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )}{e^6}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^4}-\frac{4 a d x}{e^5}-\frac{4 b d x \log \left (c x^n\right )}{e^5}-\frac{b d^4 n}{6 e^6 (d+e x)^2}+\frac{13 b d^3 n}{6 e^6 (d+e x)}+\frac{13 b d^2 n \log (x)}{6 e^6}+\frac{47 b d^2 n \log (d+e x)}{6 e^6}+\frac{4 b d n x}{e^5}-\frac{b n x^2}{4 e^4} \]
Antiderivative was successfully verified.
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Rule 43
Rule 2351
Rule 2295
Rule 2304
Rule 2319
Rule 44
Rule 2314
Rule 31
Rule 2317
Rule 2391
Rubi steps
\begin{align*} \int \frac{x^5 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^4} \, dx &=\int \left (-\frac{4 d \left (a+b \log \left (c x^n\right )\right )}{e^5}+\frac{x \left (a+b \log \left (c x^n\right )\right )}{e^4}-\frac{d^5 \left (a+b \log \left (c x^n\right )\right )}{e^5 (d+e x)^4}+\frac{5 d^4 \left (a+b \log \left (c x^n\right )\right )}{e^5 (d+e x)^3}-\frac{10 d^3 \left (a+b \log \left (c x^n\right )\right )}{e^5 (d+e x)^2}+\frac{10 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^5 (d+e x)}\right ) \, dx\\ &=-\frac{(4 d) \int \left (a+b \log \left (c x^n\right )\right ) \, dx}{e^5}+\frac{\left (10 d^2\right ) \int \frac{a+b \log \left (c x^n\right )}{d+e x} \, dx}{e^5}-\frac{\left (10 d^3\right ) \int \frac{a+b \log \left (c x^n\right )}{(d+e x)^2} \, dx}{e^5}+\frac{\left (5 d^4\right ) \int \frac{a+b \log \left (c x^n\right )}{(d+e x)^3} \, dx}{e^5}-\frac{d^5 \int \frac{a+b \log \left (c x^n\right )}{(d+e x)^4} \, dx}{e^5}+\frac{\int x \left (a+b \log \left (c x^n\right )\right ) \, dx}{e^4}\\ &=-\frac{4 a d x}{e^5}-\frac{b n x^2}{4 e^4}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^4}+\frac{d^5 \left (a+b \log \left (c x^n\right )\right )}{3 e^6 (d+e x)^3}-\frac{5 d^4 \left (a+b \log \left (c x^n\right )\right )}{2 e^6 (d+e x)^2}-\frac{10 d^2 x \left (a+b \log \left (c x^n\right )\right )}{e^5 (d+e x)}+\frac{10 d^2 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{e^6}-\frac{(4 b d) \int \log \left (c x^n\right ) \, dx}{e^5}-\frac{\left (10 b d^2 n\right ) \int \frac{\log \left (1+\frac{e x}{d}\right )}{x} \, dx}{e^6}+\frac{\left (5 b d^4 n\right ) \int \frac{1}{x (d+e x)^2} \, dx}{2 e^6}-\frac{\left (b d^5 n\right ) \int \frac{1}{x (d+e x)^3} \, dx}{3 e^6}+\frac{\left (10 b d^2 n\right ) \int \frac{1}{d+e x} \, dx}{e^5}\\ &=-\frac{4 a d x}{e^5}+\frac{4 b d n x}{e^5}-\frac{b n x^2}{4 e^4}-\frac{4 b d x \log \left (c x^n\right )}{e^5}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^4}+\frac{d^5 \left (a+b \log \left (c x^n\right )\right )}{3 e^6 (d+e x)^3}-\frac{5 d^4 \left (a+b \log \left (c x^n\right )\right )}{2 e^6 (d+e x)^2}-\frac{10 d^2 x \left (a+b \log \left (c x^n\right )\right )}{e^5 (d+e x)}+\frac{10 b d^2 n \log (d+e x)}{e^6}+\frac{10 d^2 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{e^6}+\frac{10 b d^2 n \text{Li}_2\left (-\frac{e x}{d}\right )}{e^6}+\frac{\left (5 b d^4 n\right ) \int \left (\frac{1}{d^2 x}-\frac{e}{d (d+e x)^2}-\frac{e}{d^2 (d+e x)}\right ) \, dx}{2 e^6}-\frac{\left (b d^5 n\right ) \int \left (\frac{1}{d^3 x}-\frac{e}{d (d+e x)^3}-\frac{e}{d^2 (d+e x)^2}-\frac{e}{d^3 (d+e x)}\right ) \, dx}{3 e^6}\\ &=-\frac{4 a d x}{e^5}+\frac{4 b d n x}{e^5}-\frac{b n x^2}{4 e^4}-\frac{b d^4 n}{6 e^6 (d+e x)^2}+\frac{13 b d^3 n}{6 e^6 (d+e x)}+\frac{13 b d^2 n \log (x)}{6 e^6}-\frac{4 b d x \log \left (c x^n\right )}{e^5}+\frac{x^2 \left (a+b \log \left (c x^n\right )\right )}{2 e^4}+\frac{d^5 \left (a+b \log \left (c x^n\right )\right )}{3 e^6 (d+e x)^3}-\frac{5 d^4 \left (a+b \log \left (c x^n\right )\right )}{2 e^6 (d+e x)^2}-\frac{10 d^2 x \left (a+b \log \left (c x^n\right )\right )}{e^5 (d+e x)}+\frac{47 b d^2 n \log (d+e x)}{6 e^6}+\frac{10 d^2 \left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac{e x}{d}\right )}{e^6}+\frac{10 b d^2 n \text{Li}_2\left (-\frac{e x}{d}\right )}{e^6}\\ \end{align*}
Mathematica [A] time = 0.297395, size = 249, normalized size = 1.09 \[ \frac{120 b d^2 n \text{PolyLog}\left (2,-\frac{e x}{d}\right )+\frac{4 d^5 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^3}-\frac{30 d^4 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^2}+\frac{120 d^3 \left (a+b \log \left (c x^n\right )\right )}{d+e x}+120 d^2 \log \left (\frac{e x}{d}+1\right ) \left (a+b \log \left (c x^n\right )\right )+6 e^2 x^2 \left (a+b \log \left (c x^n\right )\right )-48 a d e x-48 b d e x \log \left (c x^n\right )-2 b d^2 n \left (\frac{d (3 d+2 e x)}{(d+e x)^2}-2 \log (d+e x)+2 \log (x)\right )-120 b d^2 n (\log (x)-\log (d+e x))+30 b d^2 n \left (\frac{d}{d+e x}-\log (d+e x)+\log (x)\right )+48 b d e n x-3 b e^2 n x^2}{12 e^6} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.204, size = 1153, normalized size = 5. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{6} \, a{\left (\frac{60 \, d^{3} e^{2} x^{2} + 105 \, d^{4} e x + 47 \, d^{5}}{e^{9} x^{3} + 3 \, d e^{8} x^{2} + 3 \, d^{2} e^{7} x + d^{3} e^{6}} + \frac{60 \, d^{2} \log \left (e x + d\right )}{e^{6}} + \frac{3 \,{\left (e x^{2} - 8 \, d x\right )}}{e^{5}}\right )} + b \int \frac{x^{5} \log \left (c\right ) + x^{5} \log \left (x^{n}\right )}{e^{4} x^{4} + 4 \, d e^{3} x^{3} + 6 \, d^{2} e^{2} x^{2} + 4 \, d^{3} e x + d^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b x^{5} \log \left (c x^{n}\right ) + a x^{5}}{e^{4} x^{4} + 4 \, d e^{3} x^{3} + 6 \, d^{2} e^{2} x^{2} + 4 \, d^{3} e x + d^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 127.016, size = 598, normalized size = 2.61 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \log \left (c x^{n}\right ) + a\right )} x^{5}}{{\left (e x + d\right )}^{4}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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